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WGU Data Management – Foundations Exam Sample Questions (Q45-Q50):

NEW QUESTION # 45
Which property of an entity can become a column in a table?

• A. Uniqueness
• B. Non-null values
• C. Attribute
• D. Modality

Answer: C

Explanation:
Indatabase design,attributesof an entity becomecolumnsin a relational table.
Example Usage:
For anEmployee entity, attributes might include:

CREATE TABLE Employees (
EmployeeID INT PRIMARY KEY,
Name VARCHAR(50),
Salary DECIMAL(10,2),
DepartmentID INT
);
* Eachattribute(e.g., Name, Salary) becomes acolumnin the table.
Why Other Options Are Incorrect:
* Option A (Modality) (Incorrect):Describesoptional vs. mandatoryrelationships, not table structure.
* Option B (Uniqueness) (Incorrect):Ensuresdistinct valuesbutis not a column property.
* Option D (Non-null values) (Incorrect):Ensures thatcolumns must contain databut doesnot define attributes.
Thus, the correct answer isAttribute, as attributes of entities becometable columns.

 

NEW QUESTION # 46
Which elements are represented by attributes in the database design documents?

• A. Synonyms
• B. Repositories
• C. Relationships
• D. Names

Answer: D

Explanation:
Attributesin a databaserepresent the properties (names, values, or characteristics) of an entity.
Example Usage:
* In aStudentstable, attributes might include:
StudentID (Primary Key), Name, Age, Major
* Here,Name is an attributedescribing the entityStudent.
Why Other Options Are Incorrect:
* Option A (Synonyms) (Incorrect):Synonyms in SQL allow different names for the same object but are not attributes.
* Option C (Repositories) (Incorrect):A repository stores data butdoes not define attributes.
* Option D (Relationships) (Incorrect):Relationships defineconnections between entities, not their attributes.
Thus, the correct answer isNames, asattributes define entity properties.

 

NEW QUESTION # 47
Which command is used to filter group results generated by the GROUP BY clause?

• A. REPLACE
• B. WHERE
• C. WITH
• D. HAVING

Answer: D

Explanation:
TheHAVINGclause is used in SQL to filtergrouped resultsgenerated by the GROUP BY clause. Unlike WHERE, which filters individual rowsbeforegrouping, HAVING filtersafter aggregationhas been performed.
Example Usage:
sql
SELECT Department, AVG(Salary) AS AvgSalary
FROM Employees
GROUP BY Department
HAVING AVG(Salary) > 50000;
* This query first groups employees by Department, calculates theaverage salary per department, and then filters onlythose departments where the average salary is greater than 50,000.
Why Other Options Are Incorrect:
* Option A (REPLACE) (Incorrect):Used for string substitution, not filtering.
* Option C (WITH) (Incorrect):Used inCommon Table Expressions (CTEs), not for filtering.
* Option D (WHERE) (Incorrect):Used forrow-level filtering before aggregation, but itcannot be used on aggregate functions like SUM() or AVG().
Thus,HAVING is the correct answerfor filtering after grouping.

 

NEW QUESTION # 48
Which function is considered an aggregate function?

• A. ABS
• B. MAX
• C. DESC
• D. TRIM

Answer: B

Explanation:
Aggregate functionsperform calculationson a set of values and return asingle result.MAX()is one such function, returning thelargest value in a column.
Common Aggregate Functions:
A screenshot of a computer AI-generated content may be incorrect.

Example Usage:
sql
SELECT MAX(Salary) FROM Employees;
* Retrieves thehighest salaryin the Employees table.
Why Other Options Are Incorrect:
* Option B (TRIM) (Incorrect):Removes spaces from strings butis not an aggregate function.
* Option C (ABS) (Incorrect):Returns theabsolute value of a numberbut doesnot aggregate multiple rows.
* Option D (DESC) (Incorrect):Used in ORDER BY forsorting in descending order,not for aggregation.
Thus, the correct answer isMAX(), as it is atrue aggregate function.

 

NEW QUESTION # 49
How many bytes of storage does a BIGINT data type hold in MySQL?

• A. 4 bytes
• B. 1 byte
• C. 8 bytes
• D. 3 bytes

Answer: C

Explanation:
In MySQL, theBIGINTdata type is a64-bit integerthat requires8 bytes (64 bits) of storage. It is used to store large numerical values beyond the range of INT (4 bytes).
* Option A (Incorrect):1 byte corresponds toTINYINT, which can store values from -128 to 127.
* Option B (Incorrect):3 bytes is not a standard integer storage size in MySQL.
* Option C (Incorrect):4 bytes corresponds toINT, which has a range of -2,147,483,648 to
2,147,483,647.
* Option D (Correct):BIGINT takes8 bytesand supports a massive range of numbers from -2

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